Skip to main content

Inductor's voltage, current, and energy

Problem-Solving Strategy for solving the Inductor's voltage, current, and energy

STEP 1. The current of inductor is: $v(t)=L\frac{di(t)}{dt}$

STEP 2. The voltage of inductor is: $i(t)=i(t_0)+\frac{1}{L} \intop\nolimits_{t_0}^{t}v(x) dx$

STEP 3. The energy of inductor is: $w_L(t)=\frac{1}{2}Li^2(t)$

PROBLEM:

Basic Engineering Circuit Analysis Problem 6.33
Note: This post is based on Irwin's Basic Engineering Circuit Analysis 11th ed. 
If there are any errors in solution, please let me know in the comments

SOLUTION:

The voltage across inductor $v(t)$ is

$v(t)= \begin{Bmatrix}0&(t<0)\\-50mV &(0 \leq t<20ms)\\75mV &(20ms \leq t<40ms)\\0 &(40ms \leq t<60ms)\\-50mV &(60ms \leq t<70ms)\\0 &(t\geq 70ms)\end{Bmatrix}$

Additionally, the voltage waveform is shown as:
The waveform of inductor's voltage

Related Post: Capacitor's voltage, current, and energy
Labels:

Comments

Post a Comment